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UNIT
14
14.1: Translate a Figure
5
Figure $$ABCD$$ is mapped to Figure $$A′B′C′D’$$ by the translation $$(x,\; y) \longrightarrow (x \;+ \;0,\; y \;+\; 6)$$. Graph Figure $$A′B′C′D’$$.
• $$x + 0$$ means move the preimage $$0$$ units left (or right since it is $$0$$)
• $$y + 6$$ means move the preimage $$6$$ units up
• $$(x,\; y) \longrightarrow (x \;+\; 0,\; y\; +\; 6)$$ means move $$A,\; B,\; C$$ and $$D\; 6$$ units up.

6
The image of $$\triangle ABC$$ is $$\triangle A'B'C'$$. Graph and label $$\triangle A'B'C'$$ after the translation $$( x,\;y)\longrightarrow (x\;+\;6,\;y\;+\;4)$$.
• $$x \;+\; 6$$ means move the preimage $$6$$ units right
• $$y\; +\; 4$$ means move the preimage $$4$$ units up
• $$(x,\; y) \longrightarrow (x \;+\; 6,\; y \;+ \;4)$$ means moving vertices $$A,\; B,\; C\; and\; D \;6$$ units right and $$4$$ units up.